# Angle on a ring

**URL:** <https://discourse.shapr3d.com/t/angle-on-a-ring/7878>\
**Category:** Modeling Questions\
**Created:** [June 5, 2020, 10:14am UTC](https://discourse.shapr3d.com/t/angle-on-a-ring/7878 "2020-06-05T10:14:56Z")\
**Posts on this page:** 3\
**Page:** 1

<div class="post-metadata">

**Author:** ![Bizzaro](https://sea2.discourse-cdn.com/flex002/user_avatar/discourse.shapr3d.com/bizzaro/32/3854_2.png) [@Bizzaro](https://discourse.shapr3d.com/u/Bizzaro)\
**Post date:** [June 5, 2020, 10:14am UTC](https://discourse.shapr3d.com/t/angle-on-a-ring/7878/1 "2020-06-05T10:14:56Z")

</div>

I had to remake the model from my previous post. Because I altered to size I couldn’t reliably do what I did last time. Is there a way to basically cut a ring on an angle?

In this video you see it won’t do it all the way from a bevel. [https://share.icloud.com/photos/0ueWLXNznf4RlcsHmpgDFYbxg](https://share.icloud.com/photos/0ueWLXNznf4RlcsHmpgDFYbxg)

I can’t think of a way to "subtract” reliably to achieve this effect. Any tips?

 ![image](https://us1.discourse-cdn.com/flex002/uploads/shapr3d/original/2X/c/cff70101d484378e351f2d0f858a25a95ac32899.jpeg)

---

<div class="post-metadata">

**Author:** ![Gelphyn](https://avatars.discourse-cdn.com/v4/letter/g/db5fbb/32.png) [@Gelphyn](https://discourse.shapr3d.com/u/Gelphyn)\
**Post date:** [June 5, 2020, 1:01pm UTC](https://discourse.shapr3d.com/t/angle-on-a-ring/7878/2 "2020-06-05T13:01:28Z")

</div>

@Bizzaro  
Create a Triangular **Closed Shape** and Revolve it about the Centre of the Ring.

---

<div class="post-metadata">

**Author:** ![Bizzaro](https://sea2.discourse-cdn.com/flex002/user_avatar/discourse.shapr3d.com/bizzaro/32/3854_2.png) [@Bizzaro](https://discourse.shapr3d.com/u/Bizzaro)\
**Post date:** [June 5, 2020, 9:47pm UTC](https://discourse.shapr3d.com/t/angle-on-a-ring/7878/3 "2020-06-05T21:47:07Z")

</div>

Ah yes. That makes sense. I didn’t even think of the revolve option. Thanks.
