# How to achieve this kind of a curvature on a body?

**URL:** <https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072>\
**Category:** Modeling Questions\
**Created:** [November 25, 2023, 8:06am UTC](https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072 "2023-11-25T08:06:01Z")\
**Posts on this page:** 7\
**Page:** 1

<div class="post-metadata">

**Author:** ![Meliodas](https://avatars.discourse-cdn.com/v4/letter/m/9e8a1a/32.png) [@Meliodas](https://discourse.shapr3d.com/u/Meliodas)\
**Post date:** [November 25, 2023, 8:06am UTC](https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072/1 "2023-11-25T08:06:01Z")

</div>

I have been trying to recreate a 3D body for days with no success. I am able to replicate the whole design except a curvature. Here are a couple of screenshots of the design, with the curve troubling me highlighted:

 ![glass_front](https://us1.discourse-cdn.com/flex002/uploads/shapr3d/original/3X/d/d/dd16924c5b3848932030639bfa7eb0ca80cc7a32.jpeg)

 ![glass](https://us1.discourse-cdn.com/flex002/uploads/shapr3d/original/3X/5/a/5adb95cad465c41f6c13687786a2c593ef8f445a.jpeg)

I don’t understand how to extrude inwards with a curvature like that ! Is it possible to do this in Shapr ? the screenshots I shared are from a different unknown CAD software.

---

<div class="post-metadata">

**Author:** ![JST](https://avatars.discourse-cdn.com/v4/letter/j/edb3f5/32.png) [@JST](https://discourse.shapr3d.com/u/JST)\
**Post date:** [November 25, 2023, 9:02am UTC](https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072/2 "2023-11-25T09:02:17Z")

</div>

Subtract with a rounded body

---

<div class="post-metadata">

**Author:** ![Meliodas](https://avatars.discourse-cdn.com/v4/letter/m/9e8a1a/32.png) [@Meliodas](https://discourse.shapr3d.com/u/Meliodas)\
**Post date:** [November 26, 2023, 10:12am UTC](https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072/3 "2023-11-26T10:12:22Z")

</div>

Im sorry @JST , I am completely new to any kind of CAD software, I know what subtracting means, but I don’t understand what you are asking me to do ? can you show me how to do it ?

---

<div class="post-metadata">

**Author:** ![JST](https://avatars.discourse-cdn.com/v4/letter/j/edb3f5/32.png) [@JST](https://discourse.shapr3d.com/u/JST)\
**Post date:** [November 26, 2023, 11:33am UTC](https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072/4 "2023-11-26T11:33:33Z")

</div>

Try this method

---

<div class="post-metadata">

**Author:** ![JST](https://avatars.discourse-cdn.com/v4/letter/j/edb3f5/32.png) [@JST](https://discourse.shapr3d.com/u/JST)\
**Post date:** [November 26, 2023, 11:35am UTC](https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072/5 "2023-11-26T11:35:51Z")

</div>

You can multiply the rounded body with the pattern tool, and after use the subtract tool

---

<div class="post-metadata">

**Author:** ![JST](https://avatars.discourse-cdn.com/v4/letter/j/edb3f5/32.png) [@JST](https://discourse.shapr3d.com/u/JST)\
**Post date:** [November 26, 2023, 1:05pm UTC](https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072/6 "2023-11-26T13:05:09Z")

</div>

a little rough…but may be help

 ![IMG_1340](https://us1.discourse-cdn.com/flex002/uploads/shapr3d/original/3X/b/c/bce3d369cd7ef8396b945bc42218f5d897c4fe89.jpeg)  
 ![IMG_1339](https://us1.discourse-cdn.com/flex002/uploads/shapr3d/original/3X/3/3/338a55615853cd4f94080c4fd48f08897fedef5c.jpeg)

---

<div class="post-metadata">

**Author:** ![pwnts](https://sea2.discourse-cdn.com/flex002/user_avatar/discourse.shapr3d.com/pwnts/32/23778_2.png) [@pwnts](https://discourse.shapr3d.com/u/pwnts)\
**Post date:** [November 26, 2023, 1:51pm UTC](https://discourse.shapr3d.com/t/how-to-achieve-this-kind-of-a-curvature-on-a-body/29072/7 "2023-11-26T13:51:25Z")

</div>

@Meliodas Check out this video it may be helpful: [https://youtu.be/3rON1r88XY4?si=W1kRDrwx151a4GqW](https://youtu.be/3rON1r88XY4?si=W1kRDrwx151a4GqW)
